49.1=t^2

Solution for 49.1=t^2 equation:

49.1=t^2

We move all terms to the left:

49.1-(t^2)=0

We add all the numbers together, and all the variables

-1t^2+49.1=0

a = -1; b = 0; c = +49.1;
Δ = b2-4ac
Δ = 02-4·(-1)·49.1
Δ = 196.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{196.4}}{2*-1}=\frac{0-\sqrt{196.4}}{-2}
=-\frac{\sqrt{}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{196.4}}{2*-1}=\frac{0+\sqrt{196.4}}{-2}
=\frac{\sqrt{}}{-2}
$